Bottling Company Case Study - 550 Words

Bottling Company Case Study (Essay Sample) Content: Bottling Company Case StudyStudentà ¢Ã¢â€š ¬s NameProfessorà ¢Ã¢â€š ¬s NameCourse TitleDateBottling Company Case StudyDataNumber Ounces Number Ounces Number Ounces 1 14.5 11 15 21 14.1 2 14.6 12 15.1 22 14.2 3 14.7 13 15 23 14 4 14.8 14 14.4 24 14.9 5 14.9 15 15.8 25 14.7 6 15.3 16 14 26 14.5 7 14.9 17 16 27 14.6 8 15.5 18 16.1 28 14.8 9 14.8 19 15.8 29 14.8 10 15.2 20 14.5 30 14.6 Mean Median and Standard DeviationMean.x=ÃŽÂ £xNWherex=mean of the samplex=the ounces of each bottle in the sampleN=the total number of bottlesx=446.1 ounces30x=14.87 ouncesMedian. When arranged in ascending order, the ounces are as follows:Number Ounces Number Ounces Number Ounces 1 14 11 14.6 21 15 2 14 12 14.7 22 15 3 14.1 13 14.7 23 15.1 4 14.2 14 14.8 24 15.2 5 14.4 15 14.8 25 15.3 6 14.5 16 14.8 26 15.5 7 14.5 17 14.8 27 15.8 8 14.5 18 14.9 28 15.8 9 14.6 19 14.9 29 16 10 14.6 20 14.9 30 16.1 The median is thus 14.8 ounces.Standard deviation.s=à ¢Ã… ¡ÃƒÅ½Ã‚ £(x-x)2N-1Where:s=st andard deviationx=the ounces of each bottle in the samplex =mean of the sampleN=number of bottles in samples=à ¢Ã… ¡8.78330-1s=0.550 ounces95% Confidence Interval for the Ounces in the BottlesSince the sample size is 30, we assume that the samples are normally distributed.The critical region lies to the left of the normal distribution curve. That is, it is a one-tailed test.The corresponding Z score at 95% confidence level is -1.645. Thus:z=x-xs-1.645=x-14.870.550Solving for x we get 13.96 ounces. For the bottles to satisfy the criteria at 95% confidence level, they must be equal to or greater than 13.96 ounces.Hypothesis TestNull and alternative hypotheses.Ho: ...